Obtaining one .dwg file from each directory in a list

[Craw]

Hi, I have a list of directories that each contain several .dwg files. I would like to get the file path of one .dwg from each folder in the list and make a new list of these files for later processing.

Both lists are stored in text files. DirList.txt contains the input directories and 250List.txt contains the output dwg files.

Unfortunately, my script gives an error: "File Not Found" and appends "ECHO is off." to 250List.txt

Could someone lend me a hand in determining what is wrong with my code? Thanks.

Code: Select all

@echo off
cls
setlocal enabledelayedexpansion
FOR %%G IN (DirList.txt) DO (
for /f "delims=" %%F in ('dir %%G\*.dwg /b /o-n') do set file=%%F
echo %file%>>C:\Users\Craw\250\Last250List.txt
)
endlocal
pause

[Compo]

"delims=" should be "eol=? delims=", %%G\*.dwg should be "%%G\*.dwg", file=%%F should be "File=%%F", and the most important one, %file% should be !File!.

[Craw]

Thank you for your reply @Compo, unfortunately after making those changes, I still receive the same errors.

Code: Select all

@echo off
cls
setlocal enabledelayedexpansion
FOR %%G IN (DirList.txt) DO (
for /f "eol=? delims=" %%F in ('dir "%%G\*.dwg" /b /o-n') do set "File=%%F"
echo !File!>>"C:\Users\Craw\250\Last250List.txt"
)
endlocal
pause

[Squashman]

FOR /F is used to read a file.

[Compo]

Okay now, based on the adivce of Squashman, change:

Code: Select all

FOR %%G IN (DirList.txt) DO (

To:

Code: Select all

For /F "UseBackQ EOL=? Delims=" %%G In ("DirList.txt") Do (

[Craw]

Thank you @Squashman and @Compo.