How do I specify the " character as a delimiter in FOR

[melliott]

I want to parse a string with FOR /F where the delimiter character is the double-quote character (i.e. ")

for example, the contentes of C:\temp.out is:

name = "Joe"


I want to use something like

FOR /F "tokens=1,2 delims=^"" %%I in (temp.out) do @echo =%%J

and I'd like it to print

Joe


But I can't get FOR to treat " as a delimiter. I tried to escape it with ^", but no luck.

Any ideas?

Thanks.

[jeb]

Hi melliott,

I can see your problem, but can't solve it a "nice" way, but I can solve it in two steps.

First reading a complete line,
then replacing all " to another "unsued" character (I use #),
then splitting it with another FOR /F.

Code: Select all

@echo off
SETLOCAL ENABLEDELAYEDEXPANSION
SETLOCAL ENABLEEXTENSIONS

FOR /F "tokens=*" %%I in (temp.out) do (
  set par=%%I
  set por=!par:"=#!
  for /F "tokens=1,2 delims=#" %%J in ("!por!") DO echo %%K
)

bye
Jan Erik

[DosItHelp]

If the parsing allows '=' and ' ' as delimiters then you could use the tilde to remove quotes from the resulting string in %%J. I.e.:

Code: Select all

FOR /F "tokens=1,2 delims== " %%I in (temp.out) do @echo.%%~J