giving error in path variable declaration

[vinod]

Hi,

I am using windows-2008 machine.
In my batch script i have a condition like this,

if %BIT_FLAG% == 32-bit (

set PATH=C:\Program Files (x86)\Teradata\Client\%PKGVERSION%\bin

)

when i run this it is giving me an error..

\Teradata\Client\15.10\bin was unexpected at this time.

it seems it is giving me error due to having parenthesis.. how should i make it work?

[Squashman]

Code: Select all

if %BIT_FLAG% == 32-bit (

set "PATH=C:\Program Files (x86)\Teradata\Client\%PKGVERSION%\bin"

)

[Squashman]

You may want to consider using a different variable name then PATH because PATH is already a system variable.

[foxidrive]

Or add it to the PATH variable, if that is the reason why you are using the PATH as it is intended.

[ShadowThief]

Alternatively, you could also escape the parentheses around x86 with the ^ character.

Code: Select all

set PATH_VAR=C:\Program Files ^(x86^)\Teradata\Client\%PKGVERSION%\bin

But using quotes like in Squashman's example is better because that way there is no possibility for extra spaces to be accidentally added to the end of the value.