Script only by computer name...

[gilb]

Hi,
How to run command in script only if computer name start with XXX ?
like XXX01 / XXX02 / XXX03
Thanks, Gil.

[miskox]

@echo off
if "%computername:~0,3%"=="XXX" echo Run a command

There you can insert a command.

Saso

[gilb]

What is ~0,3% for?
what ~ for?
0,3 for?

also do I need to write at the end of line "Run a command"???

Thanks

[aGerman]

What is ~0,3% for?
what ~ for?
0,3 for?

Execute SET /? or have a look at the command index.

also do I need to write at the end of line "Run a command"???

If you want to execute a command if the comparison matches then you certainly should write this command instead.

Steffen

[miskox]

If you would give us information what you want we could give you a complete solution: for example: "I want to start abc.exe if computer name starts with XXX..."

Saso

[gilb]

Did this:

---------
IF /i %computername:~0,6%%== mokedm

(Do...)

ELSE IF /i %computername:~0,5%%== moked

(Do...)
-------------

Not working
what's wrong here?

Thanks, GIl

[Squashman]

Did this:

---------
IF /i %computername:~0,6%%== mokedm

(Do...)

ELSE IF /i %computername:~0,5%%==moked

(Do...)
-------------

Not working
what's wrong here?

Thanks, GIl

I see you didn't even come close to reading the help file for the IF command.

Code: Select all

The ELSE clause must occur on the same line as the command after the IF.  For
example:

    IF /i %computername:~0,6%==mokedm  (
        echo yes
    ) ELSE (
        echo no
    )

[gilb]

howto?
IF /i %computername:~0,6%==mokedm (
echo yes
) ELSE (
echo no
)

how to do it with.. ELSE IF?

[aGerman]

I don't understand your question. Just use ELSE IF

Code: Select all

if /i "%computername:~0,6%"=="mokedm" (
  echo yes
) else if /i "%computername:~0,5%"=="abcde" (
 echo yes
) else (
  echo no
)

Steffen

[gilb]

I wrote this:

Code: Select all

IF /i 

"%computername:~0,5%"=="MOKED"(

but pc name is MOKED01

this is not runs the command in the if statemant

howto fix it?
Thanks

[Squashman]

I wrote this:
IF /i

"%computername:~0,5%"=="MOKED"(


but pc name is MOKED01

this is not runs the command in the if statemant

howto fix it?
Thanks

Going forward please use CODE tags in your responses.

Has any example we have given you shown you that you can put the IF command on its own line and the comparison on a separate line?

[gilb]

How to do it that will work?

[Squashman]

How to do it that will work?

Steffen gave you the code in his post

[gilb]

Hi,
Did this:

---------
@echo off


IF /I %COMPUTERNAME:~0,3%==PCM

(Do THIS1)

ELSE IF /i %computername:~0,3%== "PCS

(DO THIS2)

ELSE IF /i %computername:~0,2%%= "PC"

(DO THIS3)

--------------


got 3 pcs:

1 = PCM01
2= PCS01
3 = PC01

when run script on 1 - it need to do = "DO THIS1"
when run script on 2 - it need to do = "DO THIS2"
when run script on 3 - it need to do = "DO THIS3"

BUT NOTHING Happends
What I'm doing wrong?

Thanks, Gil

[ShadowThief]

Well, if it looks exactly like that, it's because your parentheses are in the wrong place. You also need parentheses on both sides of the == operator, and there were a few other typos that were breaking things.

Code: Select all

@echo off

IF /I "%COMPUTERNAME:~0,3%"=="PCM" (
	Do THIS1
) ELSE IF /i "%computername:~0,3%"=="PCS" (
	DO THIS2
) ELSE IF /i "%computername:~0,2%"=="PC"(
	DO THIS3
)