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1st batch file contains the call command

call "d:\sfd\dtsc\admt\bat\net use.bat"

Few lines from the 2nd batch file

:MENU
Echo Press 0 for Test
Echo Press 1 for Test1
Echo Press 2 for Test2
Echo Press 3 for Test3
Echo Press 4 for Test4
Echo Press 5 for EOF
Echo Press 6 for Exit
set /p input=Enter 1-6:

if %input% == 0 goto :Test
if %input% == 1 goto :Test1
if %input% == 2 goto :Test2
if %input% == 3 goto :Test3
if %input% == 4 goto :Test4
if %input% == 5 goto :EOF
if %input% == 6 goto :EXIT
:EOF
EOF
:EXIT
Exit /b

When I select :EOF it exits the 2nd batch file. Exit does also.

What command do I use in the second batch file to return to the 1st batch file?

Thanks in advance.

A script run via call will return control to the script that called it once the second script is over.

That said, there's already a command called net use, so that may be causing issues. Never name a script the same thing as a command that already exists.

Per your suggestion, I changed the second batch file to drivesmap.bat and it still doesn't return to the 1st script.

Any idea how to fix this?

Thanks

No, because it should be doing that automatically. Post your entire scripts and we'll be able to troubleshoot more effectively.

Thank you so much it worked.
As you suggested I have added a second call batch file in the original.