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Does batch have a way to deal with remainders?

I am making a calendar in batch that will account for leap years. I want to take the date and divide it by 4. If it has a remainder then it is not a leap year, if it does not then it is a leap year. I cannot find any way to draw out the remainder.

%%4 = %4 = modulus 4

and...

set /a remainder=%date%%%4,date/=4

is the same as:
set /a remainder=%date%%%4
set /a date=%date%/4

are you working on MSDOS ? if not, try using vbscript for dates.