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Split directory name & filename from a string
Posted: 29 Jan 2009 12:56
by santoshsri
Wondering if there is any way to split directory name & filename from a string that contains a complete path of file including filename.
Posted: 03 Feb 2009 22:08
by DosItHelp
santoshsri,
Use a FOR loop like this:
Code: Select all
@echo off
Set filename=C:\Documents and Settings\All Users\Desktop\Dostips.cmd
For %%A in ("%filename%") do (
Set Folder=%%~dpA
Set Name=%%~nxA
)
echo.Folder is: %Folder%
echo.Name is: %Name%
Output will be:
Folder is: C:\Documents and Settings\All Users\Desktop\
Name is: Dostips.cmd
See also the help for the FOR command:
http://www.dostips.com/DosCommandIndex.htm#FOR
DosItHelp?
Posted: 04 Feb 2009 10:37
by RElliott63
Along those same lines... what is the easiest way to deal with looping through a directory set that includes spaces (ie "Documents and Settings")?
I have a situation where I need to find specific files (wildcard search) on a drive to do a secure delete on these specific files. I know I can do this with a "Dir /s/b", but if the files are included with a directory that has spaces, there are identification situations that are hosed due to the spaces.
Currently, I am looking at:
Code: Select all
Set LookUpSet=Dir /b/s File1* File2*
For /F %%F In ('%LookUpSet%') DO (
Echo;
Echo Path: %%~fF
Echo File: %%~nxF
Echo;
Pause
)
When I get to a File1* entry that happens to be in "Documents and Settings" the reply is:
Thanks for your help!
-Rick
Posted: 04 Feb 2009 22:24
by DosItHelp
RElliott63,
FOR /F uses spaces as default delimiter. Empty the delimiter set using
FOR /F "delim=", i.e.:
Code: Select all
Set LookUpSet=Dir /b/s File1* File2*
For /F "delim=" %%F In ('%LookUpSet%') DO (
Echo;
Echo Path: %%~fF
Echo File: %%~nxF
Echo;
Pause
)
Let us know if it works for you.
Posted: 05 Feb 2009 09:11
by RElliott63
Thanks for the advice. After playing around with it yesterday afternoon, I ended up with the following:
Code: Select all
Set LookUpSet=Dir /b/s File1* File2 File3*
For /F "Delims=" %%F In ('%LookUpSet%') DO (
Set "f=%%~nxF"
Set "p=%%~pF"
CD /D "!p!"
Call :LogMsg "Flagged for Removal"
Call :RemoveFile
Call :LogMsg "Removed"
)
Code: Select all
:: File Removal
:RemoveFile
Echo --Changing Directory to: !p!
CD /D !p!
Echo --Removing File: !f!
Call :LogMsg "Removing !f! from Folder..."
SDelete -p 5 !f!
Goto:EOF
Thanks for the help!
-R