DosTips.com

Please help.
I have a statement as :
for /f "tokens=3,* delims=:. " %%a in ('"ipconfig|find "IP Address""') do set ip=%%b

This will gives me all the IP Address of the system. I would like to eliminate ONLY the first local Active IPAddress, and ignore the rest. Appreciated any help.

tom4tp,

you could try the (new) :getIPConfig function. It returns an array of all ipconfig output, from there you can access what you need.

@echo off
call:getIPConfig arr
echo.%arr[1].IPAddress%
echo.%arr[2].IPAddress%
echo.%arr[3].IPAddress%
goto:eof

rem copy :getIPConfig function from http://www.dostips.com/DtCodeCmdLib.php#Function.getIPConfig

DosItHelp?

You can use a goto statement to effectively break out of (most) for loops:


So this code will only execute the set command once, and then it'll exit the for loop and continue on.

Thanks Larry and DosItHelp,
Both method are working well, and saving my times a lot. Really appreciated you guys responded.

Thanks.

Tom P.