DosTips.com

I need help.
Line1.txt contains 1 line below and is located in the same folder as my batch file. My batch plzwork.bat is as follows: This is what I get for Version.txt below when the script is run: GRRRRRRRRRRR!!!!!!!
Question is, why does the output file Version.txt still contain the entire line from Line1.txt instead
of the result I want which is for Version.txt to equal a single line containing only "0.27.0" ???????

Thanks, just posting this has somehow enabled me to figure it out... lol
My pattern was wrong and I needed to include the option /MATCH

CALL JREPL "[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}" "" /MATCH /F Line1.txt /O "Version.txt"

feel free to add any comments, however I'm good now.... PHEW!!

Much better, though that should give you two lines of output since 0.27.0 appears twice in your source. If you want only one then you need to figure out rules for how to choose which one you want.

Also, your pattern might give the wrong result if the source includes something like the following: 1234.567.8901
Your code will yield 234.567.890 - I doubt that would be a correct result. Maybe not a problem, but you should always consider the possibility of outliers and plan accordingly.

Note that [0-9] can more easily be represented as \d

If you assume that you always want to extract from the title, then either of the following would work: There are other solutions, but those are the first two that popped into mind.

Or if you know your source only has one title, and you always want the entire title value, then: I'm just guessing, but it looks like your line1.txt might be the first line of some larger file, and you did some preprocessing to extract the first line. If I'm correct, then you can work directly with the original file If you want to get the value in an environment variable instead of a file, then remove the /O "VERSION.TXT" and add /RTN VERSION instead. The result will be in the VERSION variable when finished.


Dave Benham