Batch unzip

[d_a_r_k]

Hello, I want to make a batch file which reads computer for specified archive name and when he does find it - extract contents of the archive to directory from where the batch file has been executed.

The archive is in .7z format for this to work we will need 7-Zip Command Line version http://sourceforge.net/projects/sev...

If someone knows how to use it, could you please help me with this?

Thanks in advance

[!k]

directory from where the batch file has been executed

Current dir? Use %cd% var:

Code: Select all

7z e archive.zip -o"%cd%" *.* -r

[d_a_r_k]

I get an error "cannot find archive"

[d_a_r_k]

Maybe it is possible to make batch file find this specific archive location and put the destination path to 7-Zip command line for extraction?

[!k]

Quite so.

Code: Select all

7z e "d:\full path\archive.zip" -o"%cd%" *.* -r

[d_a_r_k]

Unfortunately I still get the same error, it cannot find the specified archive.

[!k]

Try to use the full path to 7z.exe

[d_a_r_k]

This method does not work either

[SuzyQJax]

Do you have 7z.exe in the System32 directory?

[SuzyQJax]

7z Command Description:
a Add - create a new archive, or add files to an existing archive
d Delete - remove files from an existing archive
e Extract - unarchive files
l List - display the contents of an archive
t Test - validate the integrity of an archive
u Update - overwrite existing files in an existing archive
x Extract - same as “e”, except that the files are restored to their exact original locations (if possible)

I just ran the test code and it extracted to desktop just fine.

Code: Select all

@Echo Off
:: Extracting then Expand Test.7z file from C:\Zip directory to desktop without prompt
7z.exe e "C:\Zip\test.7z"

exit