Discussion forum for all Windows batch related topics.
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darioit
- Posts: 230
- Joined: 02 Aug 2010 05:25
#1
Post
by darioit » 25 Feb 2016 07:59
Hello,
I have a zip archive "ZipArchive.7z" which inside this structure:
FolderName\Document1.pdf
FolderName\Document2.pdf
I like to put only "FolderName" into variable.
I wrote this code:
Code: Select all
7za.exe l -r "ZipArchive.7z" | FINDSTR "[0-9].D....\>" | FIND /V "\"
and the result is
2016-02-25 14:33:30 D.... 0 0 FolderName
How can I set DirZipVariable="FolderName"?
Thank you and best regards
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Squashman
- Expert
- Posts: 4486
- Joined: 23 Dec 2011 13:59
#2
Post
by Squashman » 25 Feb 2016 08:16
Give you a hint. What command do you use to capture the output of another command?
Look back at all the previous questions we have helped you with. You have used it several times.
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darioit
- Posts: 230
- Joined: 02 Aug 2010 05:25
#3
Post
by darioit » 25 Feb 2016 09:37
you're alright, sometimes I think difficult solutions for simple things, here the best solutions!
Code: Select all
@echo off
set RESULT=
for /f "delims=" %%a in ('7za.exe l -r "ZipArchive.7z" ^| findstr "[0-9].D....\>" ^| find /v "\"') do set RESULT=%%a
set FName=%RESULT:~53,50%
echo %FName%