Echo raw string to stdout

[clanmills]

Folks

I'm writing a batch file to automate a build process. I want to do:

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echo 5 | call batFile.bat

The code in batFile.bat is :

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ECHO Enter your choice:
ECHO 1. Clean All
ECHO 2. Generate XMPSDKToolkit Dynamic Win32
ECHO 3. Generate XMPSDKToolkit Static  Win32
ECHO 4. Generate XMPSDKToolkit Dynamic   x64
ECHO 5. Generate XMPSDKToolkit Static    x64
ECHO 6. Generate All

ECHO
set /P choice=Enter your choice:

ECHO your choice is %choice%

set GENERATE_ALL=Off
set NEXT_LABEL=ok

IF "%choice%"=="1" GOTO CLEANALL
IF "%choice%"=="2" GOTO 32DLL
IF "%choice%"=="3" GOTO 32LIB
IF "%choice%"=="4" GOTO 64DLL
IF "%choice%"=="5" GOTO 64LIB
IF "%choice%"=="6" GOTO GENALL

ECHO Invalid Choice, Exiting
exit /B 0

It always drops out because %choice% is '5 ' (with a blank, and possibly \r\n)

I have a work-around using Cygwin:

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 c:\cygwin64\bin\echo -n 5 | call batFile.bat

Is there a way in DOS to echo a 'raw string' to stdout?

[dbenham]

Simply remove the unwanted space before the pipe.

Also, you don't need CALL when you use a pipe.

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echo 5|batFile.bat

Dave Benham

[clanmills]

So obvious, Dave. Of course. Echo is a cmd.exe builtin and is already raw! So echo 5 |builder.bat is the raw string '5 ' Where as echo 5|builder.bat is the raw string '5'.

Thanks very much for your help. Very much appreciated.