please help me to write this

[Mohammad_Dos]

Hi,
I want to write this nombers with batch file:

1, 1, 2, 3, 5, 8, 13, 21, ...

and another batch file that I write for example 1000 and batch file write for me thousandth of nombers above.
for example when I write 4 the batch file write 3

thank u

[jeb]

Hi Mohammad_Dos,

and at which point in your batch file do you have problems?
It would be much more effective, if you can post your batch with a description of your current problems.

hope it helps
jeb

[Mohammad_Dos]

I dont know too much about dos and batch file commans. please write for me all of that

one of my problems:
how to plus 2 nomber?
for example we have:

Code: Select all

%nom1%=4
%nom2%=6

how to plus them into %nom3% ?

and more problems ...

[!k]

Code: Select all

@echo off
rem take input to num, if no input set num to 46
if "%1"=="" (set /a num=46) else (set /a num=%1)
rem set beginning values of vars $q,$r,$s to 0,0,1
set /a $q=$r=0
set /a $s=ser=1
rem start cycle from 2 to %num% by 1
for /l %%a in (2,1,%num%) do (
rem shift values of vars $q <- $r <- $s
set /a $q=$r
set /a $r=$s
rem calculation new $s
set /a $s=$q+$r
rem add new $s to serial
call set "ser=%%ser%%, %%$s%%"
)
rem output serial
echo %ser%

call serial.cmd <number>
example: serial.cmd 46
46 is maximum

[!k]

version 2

Code: Select all

@echo off
setlocal enableextensions enabledelayedexpansion
if "%1"=="" (set /a num=92) else (set /a num=%1)
set /a $q=$r=0
set /a $s=ser=1
for /l %%a in (2,1,%num%) do (
set "$q=!$r!"
set "$r=!$s!"
for /f %%s in ('clc.exe !$q!+!$r!') do set "$s=%%s"
set "ser=!ser!, !$s!"
)
echo %ser%

maximum is 92
clc.exe here: http://cmdlinecalc.sourceforge.net/

[Mohammad_Dos]

Code: Select all

@echo off
if "%1"=="" (set /a num=46) else (set /a num=%1)
set /a $q=$r=0
set /a $s=ser=1
for /l %%a in (2,1,%num%) do (
set /a $q=$r
set /a $r=$s
set /a $s=$q+$r
call set "ser=%%ser%%, %%$s%%"
)
echo %ser%

call serial.cmd 46
46 is maximum

thank u a lot !k
please explain that

[!k]

viewtopic.php?p=5671#p5671
Sorry for my English

[Mohammad_Dos]

ok
thank u
but I dont understand this line:

Code: Select all

for /l %%a in (2,1,%num%) do ...[/b] 

please explain a little about for command in this line

[!k]

FOR /L %variable IN (start,step,end) DO command [command-parameters]

The set is a sequence of numbers from start to end, by step amount.
So (1,1,5) would generate the sequence 1 2 3 4 5
and (5,-1,1) would generate the sequence 5 4 3 2 1

Code: Select all

set /a num=10
for /l %%a in (2,1,%num%) do echo counter = %%a

output:

counter = 2
counter = 3
counter = 4
counter = 5
counter = 6
counter = 7
counter = 8
counter = 9
counter = 10

[Mohammad_Dos]

FOR /L %variable IN (start,step,end) DO command [command-parameters]

The set is a sequence of numbers from start to end, by step amount.
So (1,1,5) would generate the sequence 1 2 3 4 5
and (5,-1,1) would generate the sequence 5 4 3 2 1

Code: Select all

set /a num=10
for /l %%a in (2,1,%num%) do echo counter = %%a

output:

counter = 2
counter = 3
counter = 4
counter = 5
counter = 6
counter = 7
counter = 8
counter = 9
counter = 10

that worked in batch file but doesn't work in command prompt. why?

[jeb]

Please ...

Read For /? and cmd /? and set /?

[!k]

that worked in batch file but doesn't work in command prompt. why?

In prompt you should use one % in var %x

Code: Select all

for /l %a in (2,1,%num%) do echo counter = %a