Delete substring using variable inside for /f

[Blazer]

I am trying to delete a substring from a variable using another variable inside a for /f loop.

The "Setlocal EnableDelayedExpansion" is required for other code.

The following example does not work.

Please help.

Thank you.

Code: Select all

@Echo off

for /f "delims=" %%F in ('dir /b "C:\Windows"') do (

Setlocal EnableDelayedExpansion

Set _cities="Aberdeen, London, Edinburgh"

Set _substr=Rome

Set _dummy=!_cities:!_substr!=!

Echo !_dummy!

If Not "!_dummy!"=="!_cities!" (Echo !_substr! was found.) Else (Echo !_substr! was not found.)

Endlocal

)

[aGerman]

Probably:

Code: Select all

Set _dummy=!_cities:%_substr%=!

Steffen

[Blazer]

Thank you for your input Steffen, unfortunately that does not work

Here is the new code:

Code: Select all

@Echo off

for /f "delims=" %%F in ('dir /b "C:\Windows"') do (

Setlocal EnableDelayedExpansion

Set _cities="Aberdeen, London, Edinburgh"

Set _substr=Rome

Set _dummy=!_cities:%_substr%=!

Echo !_dummy!

If Not "!_dummy!"=="!_cities!" (Echo !_substr! was found.) Else (Echo !_substr! was not found.)

Endlocal

)

[aGerman]

Is it mandatory that you set the value of _substr inside of the parenthesized block? If not, just set the value before you run the loop. Otherwise it will get more tricky:

Code: Select all

for /f "delims=" %%S in ("!_substr!") do Set _dummy=!_cities:%%S=!

Steffen

[Blazer]

That does work but I was hoping to find a way to fix the existing code without adding another for loop.

Maybe some extra exclamation or percent characters.

Thanks.

[Squashman]

Call Set "_dummy=%%_cities:!_substr!=%%"

[Blazer]

@aGerman
@Squashman

Thank you for your help

[Blazer]

This problem has been solved by both @aGerman and @Squashman

But I wonder if its possible to tweak the solution from @Squashman so that it works without the call statement?

Call Set "_dummy=%%_cities:!_substr!=%%"

Thank you