EXTRACT THE 2 FIRST LINES OF A TXT FILE AND COPY TO ANOTHER TXT FILE

[Jorgegs]

HELO FRIENDS !

I NEED a batch file to extract the 2 first lines of a txt file generated by DU.exe renamed for W7 by me, as Dudir.exe
to bypas de DU command W7. It works perfect.

The information which I get as result in a 1. txt file is:

Files: 125
Directories: 4
Size: 230.456.786 bytes
Size on disk: 230.456.786 bytes

I want to get a new 2.txt file BUT ONLY WITH THE 2 FIRST LINES

Files: 125
Directories: 4

I tryed a lot of posibilities with FOR but I'm not an expert in FOR

Please can some one help me with the correct code

Thanks in advance for the help

[Squashman]

You could give this a try.

Code: Select all

dudir.exe -n -q |findstr /b /i "Files: Directories:" >file2.txt

[npocmaka_]

this will print the first two lines of SOME_FILE.txt:

Code: Select all

break>"%temp%\empty"&&fc "%temp%\empty" "SOME_FILE.txt" /lb  2   /t |more +4|findstr /B /E /V "*****"

[Aacini]

Code: Select all

@echo off
setlocal

( set /P "line1=" & set /P "line2=" ) < input.txt
(
   echo %line1%
   echo %line2%
) > output.txt

Antonio

[Jorgegs]

Thank you very much friends

The first solution is perfect
The second close the batch file
The solution 3 give me a message "echo is desactivated"
and in any case what for and why is setlocal necessary ?

Thanks
Jorgegs